m^2+2m-76=5

Solution for m^2+2m-76=5 equation:

m^2+2m-76=5

We move all terms to the left:

m^2+2m-76-(5)=0

We add all the numbers together, and all the variables

m^2+2m-81=0

a = 1; b = 2; c = -81;
Δ = b2-4ac
Δ = 22-4·1·(-81)
Δ = 328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{328}=\sqrt{4*82}=\sqrt{4}*\sqrt{82}=2\sqrt{82}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{82}}{2*1}=\frac{-2-2\sqrt{82}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{82}}{2*1}=\frac{-2+2\sqrt{82}}{2}
$